[joegonota]

Hi all,

I am having some problem with The Binomial Distribution.

I am given some questions on this topic... I did find out the answer, but I am not sure whether I am right or not...


Suppose there are four fair dice.

Q1:
The probability of getting exactly one 6's.

A1:
Due to those fare dice would show exact one 6's in different (4 ways)

Isn't the answer is 4*[(1/6)^1]*[(5/6)^3] = 125/324 ?




Q2:
The probability of getting exactly two 6's.

A2:
There are 6 different order to have exactly two 6's

Isn't the answer is 6*[(1/6)^2]*[(5/6)^2] = 25/216 ?


Please give me some comment on it, thanks a lot.

[ebaines]

Your answers are both correct - very good!