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disneyclassics · Feb 22, 2011, 04:52 PM

galactus · Feb 23, 2011, 06:04 AM

This is not a valid identity.

Perhaps you mean:

$\frac{sin(x)+1}{cos(x)+cot(x)}=tan(x)$

This is a valid identity. Convert the cot(x) to $\frac{cos(x)}{sin(x)}$ .

$\frac{sin(x)+1}{cos(x)+\frac{cos(x)}{sin(x)}}$

Cross multiply the denominator, factor out a cos(x), cancel the resulting sin(x)+1 in the denominator with the one in the numerator, you will see a $\frac{1}{\frac{cos(x)}{sin(x)}}$ . Which equals $\frac{sin(x)}{cos(x)}=tan(x)$