[rej_ar]

I need a step by step solution to this:
(The answers are already given; I just need the computations)
Data indicates an average population weight of a fish of 40 lbs and a standard deviation of 4 lbs. Assume weight is normally distributed in the population. How probable was it to catch a tuna:
a. greater than 50 lbs Answer: 0.62%
b. less than 35 lbs Answer: 10.56%
c. between 32 and 36 lbs Answer: 13.59%
d. 36 and 48 lbs Answer: 81.85%

Thank you so much!!

[rej_ar]

Data indicates an average population weight of a fish of 40 lbs and a standard deviation of 4 lbs. Assume weight is normally distributed in the population. How probable was it to catch a tuna:
a. greater than 50 lbs
b. less than 35 lbs
c. between 32 and 36 lbs
d. 36 and 48 lbs

[rej_ar]

Data indicates an average population weight of a fish of 40 lbs and a standard deviation of 4 lbs. Assume weight is normally distributed in the population. How probable was it to catch a fish:
a. greater than 50 lbs
b. less than 35 lbs
c. between 32 and 36 lbs
d. 36 and 48 lbs

[Curlyben]

Thank you for taking the time to copy your homework to AMHD.
Please refer to this announcement: https://www.askmehelpdesk.com/financ...-b-u-font.html

[Unknown008]

You'll have to define your variable first.

Let X be the weight of a fish.

Then,

You should know what are mu and sigma.

Then, the probability that the weight is greater than a certain value x,



Then you look in your normal table and look for the probability associated with the z value.

Can you use this hint and solve your problem, then post the work that you did?