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cow7dvd · Nov 30, 2010, 05:48 PM

I need to find the equation for a graph that has no y-intercept and starts at (1,1) the graph in creases at an increasing rate and the only part of the equation I have figured out is that it goes along the lines of 2^x(2 to the power of x), how do I make this equation?

Unknown008 · Dec 1, 2010, 12:05 AM

$2^x$ does have a y-intercept...

At x = 0, $2^0 = 1$

And this line does not pass through (1, 1), but through (1, 2).

One easy curve is:

$y = \frac{1}{x}$

EDIT: This one decreases though... I'll be thinking of another one..

Maybe this will work, since y = x increases constantly and y = 1/x gradually, adding the two would give a constant increase.

$y = \frac1x + x$

or if the increase is not enough, you can boost it a little ;)

$y = \frac1x + x^5$

ebaines · Dec 1, 2010, 06:58 AM

This question is answered here:

https://www.askmehelpdesk.com/math-s...ns-530619.html

Unknown008 · Dec 1, 2010, 08:44 AM

Well, at least, the problem was more properly explained :rolleyes: