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bnhunter · Nov 12, 2010, 05:55 PM

x^2+3xy+y^2

bnhunter · Nov 12, 2010, 06:12 PM

x^2y^3 - 6xy^2 = 10

Unknown008 · Nov 12, 2010, 11:05 PM

Yes, we do offer free help, but not 'free answers'... =/

Do you know how to differentiate an expression with one variable?

$\frac{d}{dx}(2x^2 + 1) = 4x$

So, you can express the derivative of what you got as:

$\frac{d}{dx}(x^2+3xy+y^2) = \frac{d}{dx}(x^2) <br /> \frac{d}{dx}(3xy) + \frac{d}{dx}(y^2)$

You can differentiate the first part?

For the second part, let me give you an example.

$\frac{d}{dx}(4y + y^2) = 4 \frac{dy}{dx} + 2y\frac{dy}{dx}$

As you can see, you differentiate the y similar to how you differentiate x, but you just add dy/dx after differentiating.

For the middle part of your problem, use the product rule.

galactus · Nov 13, 2010, 10:21 AM

If I may. Allow me to show a method I often use for implicit diff.

Use $\frac{-F_{x}}{F_{y}}$

i.e. $x^{2}y^{3}-6xy^{2}=10$

$-F_{x}=-2y^{2}(xy-3)$

$F_{y}=3xy(xy-4)$

$\frac{-F_{x}}{F_{y}}=y'=\frac{-2y(xy-3)}{3x(xy-4)}$

Just a thought if anyone is interested.

Unknown008 · Nov 14, 2010, 03:00 AM

I wasn't sure what you did at first, but when I expanded it, I understood. Interesting method :)

You only missed a 'y' in the denominator ;)