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madskillz852000 · Sep 20, 2010, 08:52 AM

A family drove 1080 miles to their vacation lodge. Because of increased traffic density, their average speed on the return trip was decreased by 6 miles per hour and the trip took 2.5 hours longer. Determine their average speed on the way to the lodge.

Unknown008 · Sep 20, 2010, 09:23 AM

Let the average speed to the lodge by x.

The time they took to go there is given by $Time_{go} = \frac{1080}{x}$

Now, their average speed is 6 less than the first. Hence, the new average speed is (x - 6) mil/hr.

The time is given by:

$Time_{back} = \frac{1080}{x-6}$

You are then told that this time is 2.5 hours longer than the first time... Hence:

$Time_{back} - 2.5 = Time_{go}$

$\frac{1080}{x-6} - 2.5 = \frac{1080}{x}$

Solve for x now.

Post what you get! :)