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    western50's Avatar
    western50 Posts: 105, Reputation: 1
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    #1

    Sep 14, 2010, 01:12 PM
    vector
    An object moves with constant acceleration a = 2.5 m/s2 in the due North direction. At time t = 2, the velocity of the object is v0 = 5 m/s in the due East direction. What is the magnitude of the velocity at t = 4 s?

    the way to get the answer is to use Pythagorean theorem, right? I am not sure about that.
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #2

    Sep 14, 2010, 02:15 PM

    Yes - the velocity in the east direction is constant 5 m/s, and the velocity in the north direction at t = 4s is 2.5m/s^2 x 4s = 10m/s. Use Pythagorus to find the resultant vector.
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