[DyNaFeN]

>>>>>I just need part D here<<<<<


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1- heart failure is due to either natural occurrences (87%) or outside factors (13%) outside factors are related to induced substances or foreign objects. Natural occurrences are caused by arterial blockage,disease, and infection. Assume that cause of heart failure between individuals are independent .

a)what is the probability that the first patient with heart failure that enters the emergency room has the condition due to outside factors?
success probability p=0.13
=(1-0.13)^1-1* 0.13=0.13.

b)what is the probability that third patient with heart failure that enters the emergency room is the first one due to outside factors?
(1-0.13)^3-1 *0.13= 0.098

c) what is the mean number of heart failure patients with the condition due to natural causes that enter the emergency room before the first patient with heart failure from outside factors?

M=E(X)=1/p=7.7

d)what is the probability that the third patient who has heart disease die to outside factors is the 8th patient coming in ?

??

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>>>this question made me lose my mind.. please help <<<

2- your mother is making "Hareesa" with special nuts. She crushed the nuts into small parts and mixed it well with the dough . She used a rectangle shaped tray and cut the sweet into small equal pieces that are 30 gram each . If on average each piece has 6 nuts, answer the following


a- what is the most likely distribution for the number of nuts in sweet pieces?

b-if you chose 3 pieces and saw no nuts. What is the probability that the forth piece will have 5 nuts?

c-what is the probability of finding 13 nuts in a total of 2 pieces of sweets?

d- what is the probability of finding 13 nuts in 50 grams of Hareesa?


thanks in advance.

[Unknown008]

Please, avoid double posting.

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