computing normal standard distribution
I have the following equation to solve:
We are going to try to apply the Standard Normal Distribution.
The average IQ for people is 100. The standard deviation is 16. Since I can't give you an IQ test we're going to make one up for each of you.
We'll do that as follows: take your age, divide by 2 and add 100. For this response use that value as your IQ, and determine what percentage of people would have a higher IQ. (e.g. Age = 40 y. Then you would determine percentage of people who have IQ greater than 120.)
This is what I came up with. Can you tell me if this is correct and if not where am I going wrong?
The IQ I am solving for is 44/2 + 100 = 122
122-100/16 = 22/16= 1.375
P(x>122) = P(z>1.375)
P(z>1.375 = 1-P(z<1.375)
= 1-0.9147 = 0.0853 = 8.5% people have an IQ of 122 or higher
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