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    enano37's Avatar
    enano37 Posts: 1, Reputation: 1
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    #1

    Jan 30, 2010, 11:08 PM
    Let f(x)=2x to the second power+5x-3 Find the values of f(0), f(-3),f(1/2), f(a), f(-
    Let f(x) = 2x to the second power +5x-3
    Find the values of f(0), f(-3), f(1/2), f(a), f(-b) and f (a-b)

    Does anyone know the answer?
    KISS's Avatar
    KISS Posts: 12,510, Reputation: 839
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    #2

    Jan 30, 2010, 11:25 PM

    Whatever is in the parenthesis, substitute for x.

    If f(x) = 2x then f(3) = (2)(3) =6

    F(a-5) would be 2(a-5) or 2a-10 or a-5; that''s a strange answer

    You try:
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #3

    Feb 1, 2010, 09:03 AM

    I think what he meant was this:



    But as KISS suggests, just substitute whatever value of x you are given into the formula. We call this "plug and chug." For example, if x = 2, you have:



    See how it works?
    KISS's Avatar
    KISS Posts: 12,510, Reputation: 839
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    #4

    Feb 1, 2010, 10:14 AM

    True. I knew that, I just took another simpler example and added the (a-5) case.
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