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    thanlong01's Avatar
    thanlong01 Posts: 7, Reputation: 1
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    #1

    Oct 25, 2009, 03:56 PM
    What will happen to the cell voltage? Electrochemistry
    c)If 10.0 ml of 3.0 molar AgNO3 solution is added to the half cell on the right what will happen to the cell voltage? Explain.
    d)If 20.0 ml of distilled water is added to both half cells, the cell voltage decreases. Explain

    _____________________________________
    | |
    | ______Volmeter______ |
    | | | |
    | | _K+____NO3_ | |
    | | | Salt bridge | | |
    | | []Cd | | | | []Ag | |
    | | _[] __ |_ | | |_ []___ | |
    | | [] | | | | [] | |
    | | | | | |
    | | _______ | |_______|
    100 ml 10ml
    1 M Cd(NO3)2 1M AgNO3

    My net equation is
    Sr(s) --> Sr(2+) + 2e- 2.89V
    Mg(2+) + 2e- --> Mg(s) -2.37V
    E cell = 0.52V
    Net : 2Ag+ Cd(s) --> 2Ag(s) + Cd(2+)
    thanlong01's Avatar
    thanlong01 Posts: 7, Reputation: 1
    New Member
    		  
    #2

    Oct 25, 2009, 03:58 PM

    Sr I try to draw the picture by line and I forgot to review before post so it look like this.
    Perito's Avatar
    Perito Posts: 3,139, Reputation: 150
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    #3

    Oct 25, 2009, 07:54 PM
    It would be a good idea to draw a picture and attach it (click the "Go Advanced" button if it's visible. If not, there's something in "My Profile" that you can change to get it.) In any case, I clicked "Quote User" and I can see the diagram a bit more easily.

    The half-cell on the right is . If you add to it , it will inhibit the reaction so it will lower the cell voltage.

    If you dilute the solutions, there are fewer ions to react per unit volume (the concentration drops). The EMF is a function of concentration, so the voltage will drop.
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #4

    Oct 25, 2009, 10:07 PM
    Wait... why did you use the half equation of Strontium and Magnesium up there?
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