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    JDYE's Avatar
    JDYE Posts: 2, Reputation: 1
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    #1

    Sep 12, 2009, 07:23 PM
    Step by step instruction
    Chuck and Dana agree to meet in CHiago for the weekend. Chuck leaves the airport at noon traveling north at 200 mph. Dana leaves the same airport at 3:00 pm traveling south at 240 mph. At what time will they be 1920 miles apart?
    JDYE's Avatar
    JDYE Posts: 2, Reputation: 1
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    #2

    Sep 12, 2009, 07:24 PM
    Quote Originally Posted by JDYE View Post
    Chuck and Dana agree to meet in CHiago for the weekend. Chuck leaves the airport at noon traveling north at 200 mph. Dana leaves the same airport at 3:00 pm traveling south at 240 mph. At what time will they be 1920 miles apart?
    I just need to see it broken down.. I like to do problems in an easy way
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #3

    Sep 12, 2009, 09:15 PM

    It's relative velocity problem.

    1. Find the distance covered by Chuck when Dana starts, that is the distance the does after travelling for three hours (12.00 to 3.00)

    2. Find the velocity of Chuck relative to Dana.

    3. Calculate the distance that needs to be covered after 3.00. (1920 miles - [ans to 1.)

    4. With the relative velocity from 2. you can find the time required for them to cover the rest of the remaining distance from 3.

    I hope it helped! :)
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