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    gradu8's Avatar
    gradu8 Posts: 1, Reputation: 1
    New Member
     
    #1

    May 20, 2009, 02:46 PM
    How do you solve this functions
    I tried to do it multiple times but fractions always gets me frustrated :confused:

    P(y)=y^2-4y+3
    P(-/4)

    This is as far as I got

    P(y)=(-1/4)^2-4(-1/4)+3
    Perito's Avatar
    Perito Posts: 3,139, Reputation: 150
    Ultra Member
     
    #2

    May 21, 2009, 05:18 AM
    I tried to do it multiple times but fractions always gets me frustrated

    P(y)=y^2-4y+3
    P(-/4)

    This is as far as I got

    P(y)=(-1/4)^2-4(-1/4)+3


    What is P(-4)?





    What is P(-1/4)?




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