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keke-1990 · May 7, 2009, 08:32 AM

Points o,p and q are in the sam horizontal plane. P is 15m away from o in a bearring of 40 degrees from o. q is on a bearing of 130 degrees from o and pq is 17m.
Sketch a diagram to show the positions of o,p and q?

keke-1990 · May 7, 2009, 08:33 AM

I don't know

galactus · May 7, 2009, 08:40 AM

The triangle formed is a right triangle. Just get a protractor and rule and draw it.

Let north be the y axis and be bearing 0. Then, go to the right 40 degrees and measure 40

up to p.

Then, from the same y axis, measure 130 degrees and measure?

Connect p and q and the length should be 17.

To find the length unknown from o to q, just use Pythagoras. $\sqrt{17^{2}-15^{2}}$

Since it is a right triangle, you could use sine, cosine, tangent to find any angles you need.

The reason it is a right triangle is because 130-40=90. That is the angle at O.

Does that help?

keke-1990 · May 8, 2009, 03:14 PM

Thank you very much