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    afshan101's Avatar
    afshan101 Posts: 1, Reputation: 1
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    #1

    May 7, 2009, 02:06 AM
    Pump head calculation
    Can some body make an effort to teach me pump head calculations. Thank u.
    21boat's Avatar
    21boat Posts: 2,441, Reputation: 212
    Ultra Member
     
    #2

    May 7, 2009, 03:36 AM

    This should help. If you have a specific equation just post it and I can get your answer.

    Here is the formula used in the calculation process is [(Head(Ft.) X S.G.)/2.31]. Enter the values for head (in feet) and specific gravity of the fluid being pumped to yield pounds per square inch. Specific gravity is the heaviness of a substance compared to that of water, and it is expressed without units. In the metric system specific gravity is the same as in the English system. If something is 7.85 times as heavy as an equal volume of water (such as iron is) its specific gravity is 7.85. Its density is 7.85 grams per cubic centimeter, or 7.85 kilograms per liter, or 7.85 metric tons per cubic meter. By definition, the specific gravity of water is 1.
    Quantum's Avatar
    Quantum Posts: 38, Reputation: 2
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    #3

    May 20, 2009, 04:37 AM
    I had already answered a similar question. Please see;

    https://www.askmehelpdesk.com/mechan...la-313776.html

    Rate me

    Quatum

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