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Lee-1127 · May 1, 2009, 08:16 AM

How did you get 50 degrees and 20 degrees and all that

And weren't you also suppose to find the distance in cosine rule
Like subract from a certain degree and then use because rule?

I want the working for that

galactus · May 1, 2009, 08:31 AM

140-90=50.

180+20=200.

You can do it how ever you wish. It is just right triangles. Use sine and cosine.

You don't have to start a new thread, just reply to the existing topic.

Yes, the law of cosines would work. Find the angle at B, then you have the two sides, 65 and 40. That will give the distance from C back to A.

The angle at B is (140+180)-200=120.

Now, you have a=65, b=40, C=120.

$c=\sqrt{65^{2}+40^{2}=2(65)(40)cos(120)}$

That is the distance from C back to A. You can find the bearing, OK?

By the way, technically, these are not bearings, but azimuths.

140 degree azimuth written as a bearing would be S40E.

But, call it what you like.

I just drew a picture and labeled the pertinent info.

Lee-1127 · May 1, 2009, 11:54 AM

wait dude!

how did u get 180+20= 200?