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    sdlinsey's Avatar
    sdlinsey Posts: 12, Reputation: 1
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    #1

    Apr 26, 2009, 06:31 PM
    need to complete this identity
    1 - 1/2 sin(2theta) = ?
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #2

    Apr 26, 2009, 07:40 PM



    1. treat as a single term and solve for it normally. You'll end up with:



    2. However, this equation had no solutions since the sine curve never cuts the line y = 2. This ends your question.

    Or, if that was:

    1. Same procedure but end up with



    2. Find the key angle (here denoted by alpha);





    3. Determine the quadrants in which the angle is found, here it is in the first and second quadrant, where sine is both positive.

    4. Equate to your obtained angles, you'll have



    5. Finally solve for theta, you'll have 15 and 75 in degrees.
    sdlinsey's Avatar
    sdlinsey Posts: 12, Reputation: 1
    New Member
     
    #3

    Apr 26, 2009, 07:50 PM
    No see the answer has to be in sin and cos


    Quote Originally Posted by Unknown008 View Post


    1. treat as a single term and solve for it normally. You'll end up with:



    2. However, this equation had no solutions since the sine curve never cuts the line y = 2. This ends your question.

    Or, if that was:

    1. Same procedure but end up with



    2. Find the key angle (here denoted by alpha);





    3. Determine the quadrants in which the angle is found, here it is in the first and second quadrant, where sine is both positive.

    4. Equate to your obtained angles, you'll have



    5. Finally solve for theta, you'll have 15 and 75 in degrees.
    Perito's Avatar
    Perito Posts: 3,139, Reputation: 150
    Ultra Member
     
    #4

    Apr 26, 2009, 08:53 PM
    Quote Originally Posted by sdlinsey View Post


    so

    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
    Uber Member
     
    #5

    Apr 27, 2009, 10:41 AM

    Oh, sorry, I couldn't possibly know at what level of Mathematics you are... Perito gave the answer anyway...

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