Balancing half-reactions (oxidation-reduction only)
Half-reactions are fairly easy to balance. Consider this reaction:
This is the oxidation of iron. It's simple because there's nothing involved except an electron and an iron atom. It's not actually meaningful in any real sense until we have an oxidizing agent. Here's the reduction of chlorate to chloride. (whether it really goes this far is irrelevant to the discussion. We're simply balancing the equation).
This half-reaction needs more balancing. Balancing a half reaction usually involves knowing whether it's in acid or basic solution. However, you can always balance it as if it were in
acid solution, and then correct it for basic solution. I'll show you how that's done. I'm going to delete the electron for starters. We'll add it in later.
Step 1, balance the principal element. In this case, it's the
chlorine atom that's being reduced. In this case, it's trivial because there's one chlorine atom on the left and one on the right. I won't even bother to rewrite it.
Step 2, Balance oxygens by adding water
Now there are three oxygen atoms on the left and three on the right.
Step 3, Balance hydrogen atoms by adding H+
Step 4, Balance charge by adding electrons
We now have two balance half reactions. Multiply one or both of the reactions by some number so that we have the same number of electrons on one side as the other. A fully-balanced reaction shows no electrons. Electrons are only present in
half-reactions. Note that electrons must be on
opposite sides of the half reactions. In other words, one half-reaction has to be an oxidation and the other must be a reduction.
Now add the half reactions and delete things on both sides that are the same. If water or H+, for example, were on both sides, eliminate some from one side and decrease by the same amount on the other. In this case, only e- is seen on both sides.
You can add spectator ions, if you wish. Make sure you add the same ions to both sides of the equation (they are, "spectator ions", after all).
--------------------------------------------------------------------------------------------------
If you're in basic solution, use the water equilibrium to change from H+ to OH- when you're still in the half-reaction mode.