 |
|
| Browse | Ask | Answer | Search | Join/Login |
|
|
||||
|
force of gravity between two masses
A force of gravity exists between two masses. How is the initial force of gravity (F1) affected if the separation distance between them is modified in the following ways to yield a new force of gravity (F2)?
(a) The separation distance is doubled (i.e. increased by a factor of 2). F2 / F1 = ? (b) The separation distance is decreased to one-fourth of the original length. F2 / F1 = ? |
||||
|
|
|
||||
|
Newton's law of gravity: F = GMM'/R^2 F=Force of attraction between two bodies G= Gravitational Constant M= Mass of one body M' = Mass of other body R = Distance between the two bodies |
||||
|
|
| Question Tools | Search this Question |
Check out some similar questions!
Without air resistance, all objects in free-fall on earth accelerate downwards at 9.81m/s2. Yet, all objects have different Fs values... how does it make sense for different ojects to have different foces of gravity and yet to all have the same acceleration of 9.81m/s2?
Can someone please help me to understand this problem? Two 100-N weights are attached to a scale as shown. What is the reading on the scale? (I have attached the picture) The correct answer is 100N but I do not understand why it is not 200N.
What is the distance between the Moon and Earth if the mass of the Moon is 7.34 X 10^22kg, and the force of attraction between the two is 2.00 X 10^20 N? - the answer is 3.83 X 10^8 kg. I just want to know how to get there
A hollow tube is cored out through the center of the Earth to the opposite side. You jump into the tube and begin falling to the earth. When you are half way to the center how would the force of gravity at that point compare to what it was when you were on the surface.. would it be higher, lower,...
View more questions Search
|
