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    mustang63's Avatar
    mustang63 Posts: 1, Reputation: 1
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    #1

    Feb 11, 2009, 08:55 PM
    consecutive integers
    find three consecutive integers such that the sum of the second and third exceeds half of the first by 33
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
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    #2

    Feb 12, 2009, 12:55 AM

    (n+1)+(n+2) = (n/2) + 33

    Solve for n. (n is the first of the 3 integers)
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