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    Compton yo's Avatar
    Compton yo Posts: 1, Reputation: 1
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    #1

    Jan 2, 2009, 06:36 AM
    Distance&velocity stuff
    Two students live on the 2nd and 5th floor. The student on the 5th floor throws a eraser out the window to the out studenton the 2nd ,whose window is 5.6m above the ground, notices that it takes 1.4s for it to pass her window. What is the height from the 5th floor to the ground:confused::confused:
    Clough's Avatar
    Clough Posts: 26,677, Reputation: 1649
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    #2

    Jan 2, 2009, 06:48 AM

    Hi, Compton yo!

    Greetings and WELCOME to the site! I just moved your question that you had posted in Introductions to this forum topic area so that it would get the most exposure to those who are best able to answer it. Introductions is for people to introduce themselves and we try to not ask questions there.

    It can be a little confusing when first learning how to use this site! Your question will get noticed much more in this forum area.

    We would appreciate it if you would return to Introductions sometime to tell us a little about yourself though, if you would be willing to do that.

    Concerning your question, have you checked out the instructions that can be found via clicking on the following link?

    Ask Me Help Desk - Announcements in Forum : Homework Help

    Thanks!
    Shelesh's Avatar
    Shelesh Posts: 55, Reputation: 4
    Junior Member
    		  
    #3

    Feb 17, 2009, 10:19 AM

    using s = ut + 1/2at^2

    s = 0*1.4 + 1/2*9.81*1.4^2

    = 0 + 9.6138

    = 9.6138m -------- height from 2nd floor to 5th floor


    Height of 5th floor from ground = 5.6 + 9.6138

    = 15.2138m
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