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    SPARIS's Avatar
    SPARIS Posts: 1, Reputation: 1
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    #1

    Oct 30, 2008, 02:27 PM
    Algebra II quadratic story
    Can someone help me set this problem up?

    1. The area of a rectangular field is 1200m^2. Two parallel sides are fenced with aluminum at $20/m. The remaining two sides are fenced with steel at $10/m. The total cost of the fencing is $2200.

    a) What is the length of each side fenced with aluminum?
    b) What is the length of each side fenced with steel?
    eeseely's Avatar
    eeseely Posts: 100, Reputation: 3
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    #2

    Oct 31, 2008, 10:35 AM

    You have two equations with two unknown:

    Let x = the side with aluminum @$20/m
    Let y = the side with steel @$10/m

    Here are your two equations:

    (x)(y) = 1200 sq.meters

    (2 sides)($20/side)(x) + (2 sides)($10/side) = $2,200

    From the first equation, x = 1200/y

    Substitute for x in the 2nd equation.

    You will end up with a quadratic equation that you should be
    able to solve.
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