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    teslarose's Avatar
    teslarose Posts: 1, Reputation: 1
    New Member
    		  
    #1

    Oct 28, 2008, 04:24 PM
    how do I use substitution to solve each system of equations
    x=7y-4
    2x-3y=14

    :confused:


    can you help me?
    justcurious55's Avatar
    justcurious55 Posts: 4,360, Reputation: 790
    Ultra Member
    		  
    #2

    Oct 28, 2008, 06:47 PM

    2(7y-4)-3y=14
    14y-8-3y=14
    11y-8=14
    +8 +8
    11y=22
    /11 /11
    y=2

    x=7(2)-4
    x=14-4
    x=10

    (10,2)

    you plug x into the equation. You literally substitute what comes after "x=" for x in the second equation. Hope this helps
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