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Projectile motion finding displacement
A cannon on a level plain is aimed 50 degrees above the horizontal and a shell is fired with a muzzle velocity of 1000m/s toward a vertical cliff 3214 metre away. How far above the bottom does the shell strike the side wall of the cliff. My answer is 4875m but I don't know if it is right
My tecaher wants us to split things into vertical and horizontal So for HORIZONTAL I have Displacement= 3214m Velocity= 1000m/s * cos50 = 642m Time= 5s VERTICAL Displacement= 4875 Acceleration = 10m/s^2 Initial velocity =1000m/s Time= 5s Final Velocity=950m/s |
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Your analysis of the horizontal is correct - it does indeed take 5 seconds to reach the cliff. But the vertical is not quite right - you set the vertical component of the initial velocity at 1000 m/s, but it's actually 1000*sin(50) m/s. Make that change and you'll get the correct answer. |
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When calcium hydroxide reacts with sulphuric acid in a lake what calcium salt is formed |
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The salt from the sulphuric acid. You should know that. Next time, start another thread please. |
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