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    shines14's Avatar
    shines14 Posts: 1, Reputation: 1
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    #1

    Sep 3, 2008, 05:19 PM
    Solving it
    How many liters of an 18% alcohol solution must be added to a 10% alcohol solution to get 20 L of a 15 alcohol solution
    galactus's Avatar
    galactus Posts: 2,271, Reputation: 282
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    #2

    Sep 3, 2008, 07:05 PM
    You can set this up with one or two equations. I prefer one... less work.

    Let x=the amount of 18% to be added.

    Then, the amount of 10% is what remains of the 20 L not taken up by the 18%, so we have 20-x.

    So, we have

    Solve for x.

    See how to do these now.
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