[locagata48]

Can you tell me if I did this right

Mg + I2 -> MgI2
identify the limiting reactants

A) 100 atoms of Mg and 100 molecules of I2

100 atoms Mg* 1mol/6.02E32 * 24g Mg/ 1 mol =3.99E-21g Mg
100 molecules I2 * 1 mol/6.02E23 * 258g I2/ 1 mol = 4.28E-20g I2
3.99E-21g Mg * 1mol/ 24g Mg * 1mol MgI2/1 mol Mg * 282g MgI2/1mol = 4.68E-20g MgI2
4.28E-20g I2 * 1 mol/ 258g I2 * 1 mol MgI2/1mol I2 * 282g MgI2/1mol = 4.68E-20g MgI2
no limiting reactant

B) 200 atoms of Mg and 300 molecules of I2

200 atoms Mg * 1mol/6.02E23 * 24g/ 1 mol =7.97E-21g Mg
300 molecules I2 * 1mol/6.02E23 * 258g/1 mol = 1.29E-19g I2
7.97E-21g Mg * 1mol/24 g Mg * 1mol MgI2/1mol Mg * 282g MgI2/1mol = 9.36E-20g MgI2
1.29E-19g I2 * 1mol/ 258g I2 * 1mol MgI2/1mol I2 * 282g MgI2/1mol = 1.41E-19 MgI2
limiting reactant I2

C) .12 mol Mg and .08 mol I2
.12 mol Mg *1mol MgI2/1mol Mg * 282g MgI2 = 33.84g MgI2
.08 mol I2 * 1mol MgI2/1mol Mg * 282g MgI2 = 22.56 MgI2
limiting reactant I2

[ISneezeFunny]

Part B.

Check your answer. Which one's smaller?

[locagata48]

Its Mg because of the -20 I didn't even notice that thanks