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    Slybone's Avatar
    Slybone Posts: 33, Reputation: 1
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    #1

    Jul 13, 2008, 11:57 AM
    Cost Formula Representing the slope of the line
    All right So I am a bit confused.

    The question I am working on right now states the following:

    You are applying the scattergraph method and find that the regression line you have drawn passes through a data point with the following coordinates: 7,500 units and $10,000. The regression line passes through the Y axis at the $4,000 point. Which of the following is the cost formula that represents the slope of this line?

    So I figured I would use the Least-squares regression method to calculate this...

    The fact that the regression line passes through the Y axis @ $4000 would mean that the fixed cost is 4000 correct?

    using the formula y=a +bX that gives me

    Y=4000 + ?X

    but that is basically where I get lost. How do I determine the b?
    Criado's Avatar
    Criado Posts: 142, Reputation: 15
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    #2

    Jul 13, 2008, 12:13 PM
    Take a look carefully of the formula and given:

    You were given the formula Y = a + bx, where a is y-intercept and b is slope.

    Remember that coordinates are in (x,y) form thus, x and y are already given Y = a + bx

    You were also given the y-intercept which is the a Y = a + bx

    Now, all you have to do is substitute the given values to the formula to solve for b.

    Let me know your final figure. :)
    Slybone's Avatar
    Slybone Posts: 33, Reputation: 1
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    #3

    Jul 13, 2008, 12:25 PM
    I am a bit confused because a represents the total fixed cost and b represents the variable cost per unit of activity

    So according to the scatterplot graph wouldn't the total fixed cost be 4000?

    When I use 10000 as the total fixed I get
    Y=$10,000+$1.33X

    But now I think I just really confused myself ha.
    Criado's Avatar
    Criado Posts: 142, Reputation: 15
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    #4

    Jul 13, 2008, 12:31 PM
    Nope; remember the coordinate is in (x,y) form this means that if your coordinate is (1,500 units, $2,000), then X = 1,500 units and Y = $2,000.

    If you substitute it to the formula, Y = a + bX, then

    $2,000 = a + b(1,500 units)

    Got the idea? ;)

    Please let me know. :)

    By the way, fixed cost is a.

    You got this right:
    Y=4000 + ?X
    Slybone's Avatar
    Slybone Posts: 33, Reputation: 1
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    #5

    Jul 13, 2008, 12:44 PM
    All right I THINK I got it... but I am completely unsure of myself.

    Y=$4,000+$1.25X was what I ended up with.
    Criado's Avatar
    Criado Posts: 142, Reputation: 15
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    #6

    Jul 13, 2008, 12:52 PM
    Not still; can you show me how you end up with this so I can see where it went wrong?
    Slybone's Avatar
    Slybone Posts: 33, Reputation: 1
    Junior Member
     
    #7

    Jul 13, 2008, 12:57 PM
    Ah I noticed a mistake it should have been Y=$4,000+$0.80X correct? I switched the division in excel so hence the 1.25
    Slybone's Avatar
    Slybone Posts: 33, Reputation: 1
    Junior Member
     
    #8

    Jul 13, 2008, 12:57 PM
    10000 = 4000 +b (7500)
    6000 = b(7500)
    6000/7500 = b
    .80 = b

    was the new calculation
    Criado's Avatar
    Criado Posts: 142, Reputation: 15
    Junior Member
     
    #9

    Jul 13, 2008, 01:00 PM
    Correct! :)

    So, the equation should be Y = 4,000 + 0.80X

    Congratulations! :)
    Slybone's Avatar
    Slybone Posts: 33, Reputation: 1
    Junior Member
     
    #10

    Jul 13, 2008, 01:00 PM
    Ahhh Thank you, I don't know why it was so difficult for me to do such a simple equation.
    Criado's Avatar
    Criado Posts: 142, Reputation: 15
    Junior Member
     
    #11

    Jul 13, 2008, 01:02 PM
    No problem;

    The key in solving equation is to know the given first. :)

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