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cjwolverine · May 21, 2008, 08:18 PM

(2x^2 - 3x + 1)(4x^3 +4x - 3)^5

galactus · May 22, 2008, 04:57 AM

This is not an equation. It's an expression. What are you supposed to do? Find the derivative? If so, use the product rule and the chain rule.

Remember the product rule is first times derivative of second plus the second times derivative of the first.

The chain rule is derivative of outside times derivative of inside.

$(2x^{2}-3x+1)(4x^{3}+4x-3)^{5}$

$\underbrace{(2x^{2}-3x+1)}_{\text{first}}\overbrace{(5)(4x^{3}+4x-3)^{4}(\underbrace{12x^{2}+4)}_{\text{chain rule}}}^{\text{derivative of second}}+\underbrace{(4x^{3}+4x-3)^{5}}_{\text{second}}\overbrace{(4x-3)}^{\text{derivative of first}}$

See what I done? Product rule. I will let you tidy it up.

Get back with me if you're completely hung up, but I doubt if you respond back at all anyway.