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    akays's Avatar
    akays Posts: 1, Reputation: 1
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    #1

    May 19, 2008, 03:03 PM
    solving radical eqautions
    How do you solve radical equations?
    mathstinkz1's Avatar
    mathstinkz1 Posts: 1, Reputation: 1
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    #2

    May 24, 2008, 08:34 AM
    I^5 -6i^4-3i^-3i
    galactus's Avatar
    galactus Posts: 2,271, Reputation: 282
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    #3

    May 24, 2008, 11:48 AM
    Quote Originally Posted by mathstinkz1
    i^5 -6i^4-3i^-3i
    There is a pattern to the i powers

    , then it starts over.

    Suppose you wanted .

    Just divide 1703 by 4 and look at the remainder. 425 with remainder of 3. Therefore, it is equal to -1. See?


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