Check out some similar questions!

akays · May 19, 2008, 03:03 PM

How do you solve radical equations?

mathstinkz1 · May 24, 2008, 08:34 AM

I^5 -6i^4-3i^-3i

galactus · May 24, 2008, 11:48 AM

Originally Posted by mathstinkz1

i^5 -6i^4-3i^-3i

There is a pattern to the i powers

$i=1\\i^{2}=-1\\i^{3}=-1\\i^{4}=1$ , then it starts over.

Suppose you wanted $i^{1703}$ .

Just divide 1703 by 4 and look at the remainder. 425 with remainder of 3. Therefore, it is equal to -1. See?

$3i^{-3i}=3e^{\frac{3\pi}{2}}$