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    gajodhar's Avatar
    gajodhar Posts: 3, Reputation: 1
    New Member
     
    #1

    Apr 14, 2008, 08:50 AM
    Antifreeze mixture
    AN Automobile cooling system presently contains a mixture of water and anti freeze that freezes at 12 F. The owner recent moved and now needs protection against temperatures as low as -20 F. The manufacturer publishes a table which includes the fact that 12 F protection is provided with a 35% mixture, while -20 F protection requires an 80 % antifreeze mixture. How much should the owner drain off the his 9 liter coolant system and replace with pure antifreeze to get the required protection?
    galactus's Avatar
    galactus Posts: 2,271, Reputation: 282
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    #2

    Apr 14, 2008, 01:53 PM
    He starts with a 35% solution which is .35(9) antifreeze.

    He drains out an x amount: .35(9-x)

    And replaces it with the same amount of 100%: .35(9-x)+x

    This must equal .8(9)



    Solve for x.

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