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    Concretelycan's Avatar
    Concretelycan Posts: 8, Reputation: 1
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    #1

    Apr 6, 2008, 04:53 PM
    How many variations would I get
    Does anyone know how many variations I would get if I had a 6 didget code with 48 different didgets to choose from?

    How many different variation would there be!
    galactus's Avatar
    galactus Posts: 2,271, Reputation: 282
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    #2

    Apr 6, 2008, 05:35 PM
    I would assume a code indicates that order matters. In that event, you have a permutation.

    P(48,6)=8,835,488,640 different codes.
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