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    vannaboo's Avatar
    vannaboo Posts: 3, Reputation: 1
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    #1

    Feb 7, 2008, 05:51 PM
    9th grade algebra: elimination
    Im in 9th algebra && I need help with elimination..

    Does anyone know how to do this?

    Thanks

    :)
    galactus's Avatar
    galactus Posts: 2,271, Reputation: 282
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    #2

    Feb 7, 2008, 05:54 PM
    No, no one knows how. Can you please explain?
    Wondergirl's Avatar
    Wondergirl Posts: 39,354, Reputation: 5431
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    #3

    Feb 7, 2008, 05:58 PM
    Yes. It's lots of fun--one of the funnest things in algebra. Elimination by addition and subtraction or by multiplication?
    Wondergirl's Avatar
    Wondergirl Posts: 39,354, Reputation: 5431
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    #4

    Feb 7, 2008, 05:59 PM
    See this --

    https://www.askmehelpdesk.com/math-s...ion-20603.html
    vannaboo's Avatar
    vannaboo Posts: 3, Reputation: 1
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    #5

    Feb 7, 2008, 06:01 PM
    its elimination by addition && subtraction.

    the problem I need help with is:

    3x+4=19
    3x+6y=33
    Wondergirl's Avatar
    Wondergirl Posts: 39,354, Reputation: 5431
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    #6

    Feb 7, 2008, 06:03 PM
    Quote Originally Posted by vannaboo
    its elimination by addition && subtraction.

    the problem i need help with is:

    3x+4=19
    3x+6y=33
    Are you sure you copied that correctly?
    vannaboo's Avatar
    vannaboo Posts: 3, Reputation: 1
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    #7

    Feb 7, 2008, 06:18 PM
    Hahaha

    Sorry.

    I left out the y by the 4

    :)
    mama na bojana's Avatar
    mama na bojana Posts: 3, Reputation: 1
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    #8

    Feb 9, 2008, 10:24 AM
    Just imagine that any equation is like a balance
    x- box with some not known own weight
    y- basket with some not known weight

    So you are sure that 3 boxes and 4 baskets are exactly 19 kg weight
    And you know that 3 boxes and 6 baskets are giving 33 kg

    Imagine now
    You can take out from the balance same weight from the left and from the right side, the balance will still stay in equilibrium
    And do it

    Take from the left side of the second balance 3 boxes and 4 baskets, and take from the right 19 kg

    What is remaining?
    2 baskets on left equal to 14 kg
    It is logical any basket is exactly 7 kg…….
    And ooooops do we have a problem?
    4 baskets are 28 kg?
    What about the boxes?
    They are obviously foul with Helium, like balloons, they are not pushing the left side of the equations down, they are lifting, just like any quantity with negative sign.

    Any basket is lifting with force equal to?

    3*x+4*7=19
    3*x=19-28
    3*x=-9
    X=-3

    Each box is lifting with force equal by intensity to 3kg, but because this is lifting force the sign is –

    Think
    You can find similar illustrations for any system.
    You can work with prices instead of weights….

    All the best
    And more work
    simoneaugie's Avatar
    simoneaugie Posts: 2,490, Reputation: 438
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    #9

    Feb 9, 2008, 09:37 PM
    3x + 4 = 19

    Subtract 4 from both sides The 3x would stay
    The 4 disapears
    19 - 4 = 15

    Now you have 3x = 15 All you have to do now is to divide both sides by 3

    Answer: x = 5 That one is easy

    If x is the same in both problems,

    3x + 6y = 33 becomes 15 + 6y = 33


    To solve that one, subtract 15 from both sides 15 - 15 =0

    33 - 15 = 18

    The new equation is 6y = 18 What is y? It is 3.
    saoco's Avatar
    saoco Posts: 1, Reputation: 1
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    #10

    Feb 12, 2008, 06:32 PM
    For the following set of numbers, find the average. The median, and the mode. 22,16,23,17,25,25?
    morgaine300's Avatar
    morgaine300 Posts: 6,561, Reputation: 276
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    #11

    Feb 12, 2008, 08:24 PM
    Quote Originally Posted by saoco
    for the following set of numbers, find the average. the median, and the mode. 22,16,23,17,25,25?
    It would be good to start your own thread with this, especially since no one expects to find this under a thread entitled "elimination."

    Do you remember learning how to do an average clear back in elementary school? Same thing. Only usually we call it a "mean" in statistics.

    To get the medium, you will need to "order" the numbers, that is, put them from smallest to largest. Then find the middle. If you have an odd number of elements, it's literally the middle. (i.e. if you have 7 items then it's the 4th one over, the middle one.) If it's an even number, like you have, it's the average of the two center ones. (i.e. the average of the 3rd and 4th one.) That'll be easier to see once you have them ordered.

    A mode is which thing appears most often in the set.
    dh664's Avatar
    dh664 Posts: 3, Reputation: 1
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    #12

    Apr 10, 2010, 09:05 PM

    I assume you mean 3x+4y=19 so
    3x+4y=19
    3x+6y=33
    subtract the equations
    0x-2y=-14
    divide -14 by 2
    y=-7
    put -7 in for y in one of the equations
    3x+4(-7)=19
    3x-28=19
    add 28 to both sides
    3x=47
    take 47/3
    x=15.6666
    (15and2/3,-7)
    dh664's Avatar
    dh664 Posts: 3, Reputation: 1
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    #13

    Apr 10, 2010, 09:08 PM

    sorry I meant y=7 not -7

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