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\left\{x*y=3x+3y\\x^2+y^2=160} \right\ \\ x=(\frac{3x+3y}{y}) \\ (\frac{3x+3y}{y})^2 +y^2=160 \\ \frac{9x^2+18xy+9y^2}{y^2}+y^2=160 \mid *y^2 \\ 9x^2+18xy+9y^2+y^4=160y^2
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