[coliechrist5]

I can't figure this out.

There are three boys consecutive even aged. The product of the first and third boy is 20 more than twice the first
What are there ages?

[asterisk_man]

just write out all the equations and solve. I assume "consecutive even aged" means something like 10 12 14
call the three ages a b and c
a<b<c
b=a+2
c=b+2
a*c=20+2*a

Do some substitution and solving and you're done!