 |
|
|
 |
New Member
|
|
Sep 22, 2007, 06:41 PM
|
|
Slope intercept
The line through (4,0) that is perpendicular to the line x+y=3
I am sort of lost and unsure if I am on the right track.
y-0=-1(x-4)
y-0=-1x+4
+0 +0
y=-1x + 4
Is this the answer in slope intercept form:confused:
|
|
 |
Ultra Member
|
|
Sep 23, 2007, 09:14 AM
|
|
Looks good, except watch the slope. The perp line has a slope which is the negative reciprocal of the slope of the given line. The given line has slope -1, so the slope of your line is 1, not -1.
Yes, you are in slope intercept form, y=mx+b. m is the slope and b is where it crosses the y axis.
As an aside, do not write the 1 in front of the x. Makes it look rather hackneyed, though, technically it's correct.
Does that help?
|
|
 |
New Member
|
|
Sep 23, 2007, 12:00 PM
|
|
 Originally Posted by galactus
Looks good, except watch the slope. The perp line has a slope which is the negative reciprocal of the slope of the given line. The given line has slope -1, so the slope of your line is 1, not -1.
Yes, you are in slope intercept form, y=mx+b. m is the slope and b is where it crosses the y axis.
As an aside, do not write the 1 in front of the x. Makes it look rather hackneyed, though, technically it's correct.
Does that help?.
So, if I am understanding you correctly, you are saying that I do not need to put the 1 in front of the x since x by itself is an understood 1 correct? Second, the perpendicular line has a negative reciprocal of the slope given and since the answer ended with the slope being a -1 the reciprocal of that would be 1. The correct answer being... y= x - 4 ?
|
|
 |
Ultra Member
|
|
Sep 23, 2007, 12:07 PM
|
|
That should be y=x+4.
We know the slope is 1, so we can use y=mx+b to find b and finish.
4=1(0)+b, b=4
Therefore, the equation is y=x+4
|
|
 |
New Member
|
|
Sep 23, 2007, 09:14 PM
|
|
 Originally Posted by galactus
That should be y=x+4.
We know the slope is 1, so we can use y=mx+b to find b and finish.
4=1(0)+b, b=4
Therefore, the equation is y=x+4
I am not understanding why it is a positive 4
|
|
 |
New Member
|
|
Sep 23, 2007, 10:34 PM
|
|
Wrong substitution of y and x. The co ordinates that it passes through are 4,0 i.e.. x=4 y=0
Thus y= 1x + c ---> 0= 4 + c ----> c = -4
|
|
 |
Ultra Member
|
|
Sep 24, 2007, 02:56 PM
|
|
Yes, chris fixed it. I had the coordinates backwards. It is indeed y=x-4.
Sorry 'bout that.:o
|
|
Question Tools |
Search this Question |
|
|
Add your answer here.
Check out some similar questions!
Tax intercept
[ 1 Answers ]
OK, my sons father claims he filed his taxes about 3 weeks ago and he owes back support for my son. The back support is equal to 2 months of his support obligation. I know that federal taxes will be intercepted by the government in this case. How long should it take for the money to be deposited...
Slope and intercept this is it for now .
[ 2 Answers ]
1. Which line is the flattest (or is less steep)? Why?
y = 5x -6
y = 5x + 6
y = x - 3
y = x + 3
2. The line y = 4x - 7 crosses the y axis at:
(4, 0)
(0, 4)
View more questions
Search
|