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    diseth_05's Avatar
    diseth_05 Posts: 1, Reputation: 1
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    #1

    Sep 18, 2007, 10:16 PM
    Calculus Limits
    Evaluate the limit
    Lim f(x+h) – f(x)
    h →0 h


    when

    f(x) = __ 1___
    √x


    [Read as "the limit as h approaches 0 of the difference quotient {f(x+h)-f(x)}/ h when f(x) equals one over the square root of x."]


    no clue how to do this
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #2

    Sep 19, 2007, 11:00 AM
    I'll give you a hint on how to set this up and a trick you may need to solve - then you do the rest and let us know how you do, OK?

    When you put the function into the limit equation, you get this:



    Massage this a while to geta common denominator -- you'll end up with the difference of two square roots in the numerator. When that happanes a trick that almost always works is to multiply and divide that expression by the sum of the two square roots (i.e. multiply by 1). For example:


    Try this and see if it helps.

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