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    Donnanc31986's Avatar
    Donnanc31986 Posts: 1, Reputation: 1
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    #1

    Jun 28, 2007, 06:57 PM
    for a graph
    I have to find the slope-intercept of an equation...

    1. slope=2 passes through (1,5)...

    2. passes through (-1,-5) and (3,2)

    3. passes through (0,3) and is perpendicular to a line whose equation is y-7x=4?
    galactus's Avatar
    galactus Posts: 2,271, Reputation: 282
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    #2

    Jun 29, 2007, 04:09 AM
    i have to find the slope-intercept of an equation...

    1. slope=2 passes through (1,5)...
    Everything is given. Slope-intercept form is y=mx+b. You have x,y,and m. Plug those in and solve for b.

    2. passes through (-1,-5) and (3,2)
    Use the definition of slope, to find m
    You have x and y. Proceed as in #1.

    3. passes through (0,3) and is perpendicular to a line whose equation is y-7x=4?
    Solve y-7x=4 for y. It'll be in y=mx+b form. You can easily see what the slope is. The slope of the perp. Line will be the negative reciprocal of that. You have x and y, proceed as before.
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