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    hayzemay's Avatar
    hayzemay Posts: 7, Reputation: 1
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    #1

    Oct 17, 2007, 04:20 AM
    Mass percentage
    Vinegar (0.9862 g) was titrated withj 0.120 M NaOH. 26.28 cm3 were required. What is the (mass) % CH3COOH in the vinegar?

    I got an answer of 19.2% but I'm not sure can anyone help
    templelane's Avatar
    templelane Posts: 1,177, Reputation: 227
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    #2

    Oct 17, 2007, 04:51 AM
    Here's my working so you know I'm not just randomly agreeing with you. I haven't explained every step this time because if your right you must know what you're doing.


    0.120 x (26.28 /1000) = 0.003M

    MW of CH3COOH = 60.05

    mass (g) = amount (moles) x molecular weight (g/mole)


    g of CH3COOH = 0.189

    (0.189 g of acetic acid/0.9862g of vinegar)/100= 19.2%

    = YOUR RIGHT YAY!!
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