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    chris89 Posts: 10, Reputation: 3
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    Oct 1, 2007, 07:45 PM
    Common Ion Effect
    Calculate the solubility of PbCl2 at 25degrees Celsius in a solution that is 0.50M in NaCl.
    when solving am I correct in setting Ks = [s][2s+0.50]^2??
    It doesn't seem quite right.. Im not sure how to solve this WITHOUT using the assumptions that s is small. (Which is then easy to solve)

    But at any rate, the book solves is at S= Ks/ 0.5 but why isn't it Ks/(0.5)^2??

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