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triplejump38 Posts: 2, Reputation: 1

New Member

Apr 5, 2008, 05:29 PM

how do I solve

x^2 < 12x-27

galactus Posts: 2,271, Reputation: 282

Ultra Member

Apr 5, 2008, 06:25 PM

Rewrite as $x^{2}-12x+27<0$

Now factor:

$(x-9)(x-3)<0$

What values of x satisfy the inequality?

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