[Average Math Guy]

I need to solve for x but this is as far as I got.

b(x-a)=a(x-b)

How do I get x by itself? The book says the answer is 0 but I am not sure how to get to it.

[Wondergirl]

Show us the work you've done so far.

[Average Math Guy]

All right it was first like this

x-a/x-b=a/b

I then multiplied by the LCD and got b(x-a)=a(x-b).

Then I got bx-ab=ax-ab

[Wondergirl]

b(x-a)=a(x-1)
bx-ba = ax-a?

[Average Math Guy]

Sorry I wrote it wrong it is b(x-a)=a(x-b).

I am still stuck though...

[ISneezeFunny]

bx - ab = ax - ab

bx = ax

ax - bx = 0

x(a - b) = 0

x = b - a

only way answer's 0 is if a = b. perhaps you wrote the problem wrong?

[Average Math Guy]

In
bx = ax

if you divide by x then a will equal b. But will that work?