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    Chris F's Avatar
    Chris F Posts: 2, Reputation: 1
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    #1

    Jan 23, 2006, 06:37 PM
    Determining the limit of the transcendental Function.
    lim sin^2x/x

    x-0
    dmatos's Avatar
    dmatos Posts: 204, Reputation: 26
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    #2

    Mar 21, 2006, 07:50 PM
    You need to use something called "L'Hopital's Rule." Basically, if a limit is indeterminate (0/0, infintiy/infinity), then L'Hopital's rule states you can take the limit of the derivative of the numerator over the derivative of the denominator. That is,

    lim f(x)/g(x) = lim f'(x)/g'(x)

    Have a look at the wikipedia page

    http://en.wikipedia.org/wiki/L%27H%C3%B4pital%27s_rule

    specifically, at the examples, and let me know if you need more help.
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