Check out some similar questions!

mwilliams15 · Oct 3, 2007, 04:18 PM

This is a trigonometry problem. How do you find the inverse cosecant of 2, the square root of 2, and -2. The answer must be in radians. I don't want anyone to do my homework for me, I just want to know how to do it lol.

galactus · Oct 3, 2007, 04:38 PM

I assume you have a calculator with only sine, cosine, and tangent?

In that case, type in $sin^{-1}(1/2)=csc^{-1}(2), \;\ sin^{-1}(\frac{1}{\sqrt{2}})=csc^{-1}(\sqrt{2})$ and so forth.

Set your calculator to radians first. If it's in degrees, multiply by $\frac{\pi}{180}$