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    sajeevml's Avatar
    sajeevml Posts: 2, Reputation: 1
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    #1

    Sep 21, 2007, 06:20 AM
    Solve
    A stone is dropped from a tower of 100 meter height and another stone is thrown vertically up words with a velocity of 25 meter/second. When and where the two stones meet?
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #2

    Sep 21, 2007, 06:57 AM
    We're not going to do your homework for you. Please show us what efforts you have made to solve this problem, and where you're getting stuck - I'm sure someone will help you once you have demonstrated some effort.
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    sajeevml Posts: 2, Reputation: 1
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    #3

    Sep 27, 2007, 01:36 AM
    a = 9.8 ms^-2
    u = 0
    s = 100 m

    u = 25 m/s
    a = - 9.8 ms^-2
    v = 0 ms^-2

    hmmm, interesting. I'll need a second look at this one

    s = ut + 0.5 at^2
    s = 25 t - 4.9 t^2 (this is your equation for stone 2)

    s = 4.9t^2 (this is the equation for stone 1)

    Yes equate these equations and I get

    31.8877551 = s

    t = 2.551020408
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #4

    Sep 27, 2007, 03:19 PM
    Not quite. Your equation for stone 1 ignores the fact that it is dropped from a height of 100m, and the sign of the acceleration due to gravity should be negative. This equation should be:

    s = 100 - 4.9t^2.

    Your equation for stone 2 is correct: s = 25t - 4.9t^2

    Now, solve for t, and you'll get the correct answer.

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