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    Bdamathdummy08's Avatar
    Bdamathdummy08 Posts: 1, Reputation: 1
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    #1

    Sep 13, 2007, 06:46 PM
    Cubes in algebra 2
    does anyone know how to multiply (2x-1 )cubed/(2x-1)^3
    CellistJames's Avatar
    CellistJames Posts: 19, Reputation: 2
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    #2

    Sep 13, 2007, 08:10 PM
    yes think about it if x is cubed you multiply it by x 3 times so x times x times x

    so say x = 3 3 cubed is 27

    now lets say we have (x-10)squared what do you do? (x-10)(x-10) = (x-10)^2

    the same logic follows a quantity being cubed

    hope I was clear enough
    KISS's Avatar
    KISS Posts: 12,510, Reputation: 839
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    #3

    Sep 13, 2007, 09:24 PM
    I think someone is pulling their leg: something divided by itself =1
    CellistJames's Avatar
    CellistJames Posts: 19, Reputation: 2
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    #4

    Sep 13, 2007, 09:29 PM
    Quote Originally Posted by KeepItSimpleStupid
    I think someone is pulling their leg: something divided by itself =1
    Pretty sure the / was to separate the two different ways to write quantity cubed
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
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    #5

    Sep 13, 2007, 11:58 PM
    Yes, I agree with james.

    It just means (2x-1)(2x-1)(2x-1).

    You just need to sort out the first 2 brakets first, then do the 3rd set once you've simplified that.
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