What: logarithems

roxany · Aug 22, 2007, 12:38 PM

OK so I totally forgot how to do logs here's a problem I have
log (base 3) x squared = 2log (base 3)4 - 4log (base 3)5

ebaines · Aug 22, 2007, 12:49 PM

Some rules to remember about logs:
$ n \times log_a b = log_a b^n $

$ log(a/b) = log (a) - log (b) $

$ log (a*b) = log (a) + log (b) $

You can use these rules to simplify your problem. For example:

$ 4 \times log_3 5\ =\ log_3 5^2 $

Can you continue from there?

cally63 · Sep 10, 2007, 11:45 PM

Solv this logarithems 2log16(base2)+4log8(base2)-3log64(base2)

cally63 · Sep 10, 2007, 11:49 PM

Solv the logarithems:-log8(base6)+2lod3(base6)+log12(base6)-log24(base6)

Capuchin · Sep 11, 2007, 12:20 AM

You can use the rules above given by ebaines to solve these.