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    twz06's Avatar
    twz06 Posts: 7, Reputation: 1
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    #1

    Aug 28, 2007, 03:17 PM
    Constant acceleration, with initial velocity
    A bolt comes loose from the bottom of an elevator that is moving upward at a speed of 6.50 m/s. The bolt reaches the bottom of the elevator shaft in 4.55 s. How high up was the elevator when the bolt came loose?
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
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    #2

    Aug 28, 2007, 11:39 PM
    Hi, sounds like one of the suvat equations will do it.

    You know a, t, and u and you want to find s. You don't want an equation with v in it though.

    Can you identify which one you can use?
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    twz06 Posts: 7, Reputation: 1
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    #3

    Aug 29, 2007, 05:54 AM
    Would you use the equation x=xi+vi(t)+1/2at^2?? I'm still stumped
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    Capuchin Posts: 5,255, Reputation: 656
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    #4

    Aug 29, 2007, 05:56 AM
    Erm, I think that's the one.

    s = ut+1/2at^2

    just plug in the numbers and you get a reasonable looking s
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    twz06 Posts: 7, Reputation: 1
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    #5

    Aug 29, 2007, 06:04 AM
    What stands for "u" I think I have different variables, what is your u??
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
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    #6

    Aug 29, 2007, 08:53 AM
    u is normally initial velocity.

    I understand your equation now, yes that's the right one to use.

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