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I'm stuck.I hate logarithms
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After log the # after is down low and the # after ^ is the exponent a^2 is a squared. Sorry its so confusing... 1. log5^9 2. log5^3/2 3.log5^30 4.log5^10/9 5.log4^a+log4^9=log4^27 6.log7^24-log7^(y+5)=log7^8 7. 2log10^6-1/3log10^27=log10^x 8. log6^(a^2+2)+log6^2=2
Laws of logarithms
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did I solve this righ? log 2 + 3 log (X) = log 8 2 2 2 log 2Xraised to the 3rd = log 8 2 2 2X raised to the 3rd = 8 x raised to the 3rd = 8 x= squared root of 4
Logarithms... it really confuses me!
[ 4 Answers ]
OK so this time I am really trying to solve themm but I don't know how to.. I have couple of solutions but I don't think eighter of them is right: 25^x=18 log 25^x=log 18 xlog25= log 18 x=log 18/log 25 x=log 18-25 x=log (-7) but actually I am not supposed to solve it.. I am just suppose...
Logarithms
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got stuck on this one... use the properties of logarithms to rewrite the expression in terms of log(base 10)of 3 and log(base 10) of 4. Then use log(base10) of 3 = 0.477 and log (base 10) of 4 =0.602 to approximate the expression. then these are the two I have to solve. a. log (base 10) of 16... View more questions Search
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