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    nccaitlin91's Avatar
    nccaitlin91 Posts: 26, Reputation: 1
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    #1

    May 5, 2015, 12:46 PM
    derivative of y= ln (3x/tanx)
    Ok so I have another logarithmic derivative equation

    y= ln (3x/tan x)

    Normally I would do

    y1= ln 3x-ln tanx

    but i am thinking since there are trig functions, it has to be set up differently. Problems in the book are not helping me answer this problem.
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #2

    May 5, 2015, 01:41 PM
    I'm not sure what yuo mean by the term "y1" - please clarify. Do you mean deribcvitive of y?

    It is true that if ln(a/b) = ln(a) - ln(b), so if y(x)= ln(3x/tanx) then y(x) = ln(3x) - ln(tanx). But now you must find the derivatives of both of these terms.

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