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    JJJKBurke's Avatar
    JJJKBurke Posts: 3, Reputation: 1
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    #1

    Nov 6, 2012, 11:38 AM
    magic square solver
    Hi
    Can you solve a 3x3 magic square with a total of 25? Is it possible with whole numbers? Does the middle number have to be a third of the total?
    Thanks
    John B
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #2

    Nov 6, 2012, 12:58 PM
    The "standard" 3x3 magic square adds to 15. If you want it to add to any value X you can simply increment each of the entries in the "standard" version by (X-15)/3. With that you should be able to answer the first two questions. As for the third one: a little thinking about what happens if the middle number is less than 1/3 the total (or more than 1/3) and what the implications would be for the other numbers should help you get the answer.
    JJJKBurke's Avatar
    JJJKBurke Posts: 3, Reputation: 1
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    #3

    Nov 6, 2012, 01:19 PM
    Thanks
    So I presume it's not possible with total of 25 using whole integers.
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #4

    Nov 6, 2012, 01:28 PM
    Quote Originally Posted by JJJKBurke View Post
    Thanks
    So I presume it's not possible with total of 25 using whole integers.
    I believe that's correct.
    JJJKBurke's Avatar
    JJJKBurke Posts: 3, Reputation: 1
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    #5

    Nov 6, 2012, 02:13 PM
    Thanks

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